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A=2^n+3+2^n+2+2^n+1-2^n se divide cu 13 dau coroana​

Răspuns :

A=2^(n+3) +2^(n+2) +2^(n+1) -2^n

A=2ⁿ(2³+2²+2¹-1)

A=2ⁿ(8+4+2-1)

A=2ⁿ*13 ⋮ 13

Kawaiimath