Răspuns:
miu,HCl= 36,5g/mol
niu,HCl=m/miu= 730g/36,5g/mol= 20mol
2mol....1mol,,,,,,,,1mol,....1mol
2HCl + Fe----> FeCl2 + H2
20mol.....x............y............z
x=niu= 10molFe
A,Fe=56g/mol=====.>m=niuxA=10molx56g/mol=560gFe
y=niu= 10molFeCl2
z=niu=10molH2
V=niuxVm=10molx22,4 l/mol= 224 l H2
Explicație: