Răspuns:
Explicație:
1.
12,044.10 la 25 = 1204,4 .10²³
1mol NH3---------6,022.10²³ molecule NH3
xmoli NH3--------------1204,4.10²³molecule NH3
x=n= 1204,4 .10²³ : 6,022.10²³= 200 moli NH3
m= n . M
MNH3= 14 + 3=17--------> 17g/moli
m= 200moli .17g/moli= 3400 g NH3
2.
MSO3= 32 + 3.16= 80-------> 80g/moli
n= 160g : 80g/moli= 2moli SO3
1mol SO3------------ 3 . 6,022.10²³atomi O
2moli SO3----------------x
x= 2 . 3 . 6,022.10²³ = 36,132.10²³atomi O
