Răspuns:
a) x= [tex](\frac{8}{\sqrt{18} } +\frac{6}{\sqrt{2} } )*\frac{\sqrt{2} }{13} = (\frac{8}{3\sqrt{2} } +\frac{6}{\sqrt{2} } )*\frac{\sqrt{2} }{13} = \frac{26}{3\sqrt{2} }*\frac{\sqrt{2} }{13} = \frac{2}{3}[/tex]
y = [tex](\frac{1}{\sqrt{3} }-\frac{5}{7\sqrt{3} } })*\frac{14}{\sqrt{3} } = \frac{2}{7\sqrt{3} }*\frac{14}{\sqrt{3} } = \frac{2}{\sqrt{3} }*\frac{2}{\sqrt{3} } = \frac{4}{3}[/tex]
b) [tex]x+y = \frac{2}{3}+\frac{4}{3}= \frac{6}{3} = 2[/tex]
Explicație pas cu pas: