va rog , e urgent!
imi trebuie pana maine dimineata

Răspuns:
#include<iostream>
using namespace std;
int main ()
{int a, b, c, d;
cin>>a>>b>>c>>d;
if(((a+b)%2==0)&&((c-d)%2==0))
cout<<"DA" ;
else
if(((a+b) %2!=0)&&((c-d)%2!=0))
cout<<"DA" ;
else
cout<<"NU" ;
return 0;
}