Răspuns:
Explicație pas cu pas:
[tex]\large \bf a)~~ \{[5\cdot4:(-4)]^{10}:(5^2)^4-6^2\}\cdot[(-2)^2]^2-(-3^2)=[/tex]
[tex]\large \bf \{[20:(-4)]^{10}:5^8-6^2\}\cdot16+9=[/tex]
[tex]\large\bf [(-5)^{10}:5^8-36]\cdot16+9=[/tex]
[tex]\large \bf (5^2-36)\cdot16+9=[/tex]
[tex]\large \bf (25-36)\cdot16+9=[/tex]
[tex]\large\bf -11\cdot16+9=[/tex]
[tex]\large\boxed{\bf-167}[/tex]
b) {15⁰ - [(-3)² + (-5)² - (-2)⁵] : (-11)⁰ · 1 + 9} : (-2)³ =
{1 - [3² + 5² + 2⁵] : 1 + 9} : (-8) =
[1 - (9 + 25 + 32) + 9] : (-8) =
(1 - 66 + 9) : (-8) =
(-56) : (-8) =
7
[tex]\large \bf c)~~[(-8)^{36} : 2^{106} + (-9)^{54} : 3^{106} + (-5)^{48} : 25^{23}] : 2 \cdot 3 =[/tex]
[tex]\large \bf (8^{36} : 2^{106} +9^{54} : 3^{106} + 5^{48} : 25^{23}) : 2 \cdot 3 =[/tex]
[tex]\large \bf [(2^{3})^{36} : 2^{106} +(3^{2})^{54} : 3^{106} + 5^{48} : (5^{2})^{23}] : 2 \cdot 3 =[/tex]
[tex]\large \bf (2^{108} : 2^{106} +3^{108} : 3^{106} + 5^{48} : 5^{46}) : 2 \cdot 3 =[/tex]
[tex]\large \bf (2^{2} +3^{2}+5^{2}) : 2 \cdot 3 =[/tex]
[tex]\large\bf (4 +9 + 25) : 2 \cdot 3 =[/tex]
[tex]\large\bf 38 : 2 \cdot 3 =[/tex]
[tex]\large\bf 19 \cdot 3 =[/tex]
[tex]\Large \boxed{\bf 57 }[/tex]
==pav38==
