ma ajutati, va rog? multumesc))

Răspuns:
(3x-2)²-(2-3x)²-(√7-√5)(√7+√5)
(a-b)²=a²-2ab+b²
(a-b)(a+b)=a²-b²
=9x²-2×3x×2+4-(4-2×2×3x+9x²)-(√7²-√5²)
=9x²-12x+4-(4-12x+9x²)-(7-5)
=9x²-12x+4-4+12x-9x²-2
reducem termenii asemenea
=-2