Răspuns:
[tex]a) (-2)^{5}=-32 \\\\
b) (-2)^{4}=16\\\\
c) 5^{-1}=\frac{1}{5^{1}}=\frac{1}{5} \\\\
d) (-5)^{-2}=\frac{1}{(-5)^{2}}=\frac{1}{25} \\\\
e) (-3)^{2}=9 \\\\
f) (-\frac{1}{3})^{2}= \frac{(-1)^{2}}{3^{2}}=\frac{1}{9} \\\\
g) (\frac{1}{2019})^{-1}= \frac{1}{(\frac{1}{2019})^{1}} = \frac{1}{\frac{1}{2019}}= 2019\\\\
i) (-\frac{2}{5})^{-2}= \frac{1}{(-\frac{2}{5})^{2}}=\frac{1}{\frac{(-2)^{2}}{5^{2}}} =\frac{5^{2}}{(-2)^{2}} = \frac{25}{4}=6\frac{1}{4}\\\\
j) (-\frac{4}{13})^{0}=1
[/tex]
