Răspuns:
Explicație pas cu pas:
[tex]\bf a)~~\bigg(5^{17} \cdot5^{18}+7^{23}:7^{15}\bigg):\bigg(7 \cdot7^{2}\cdot7^{5}+5^{50}:5^{15}\bigg)=[/tex]
[tex]\bf \bigg(5^{17+18} +7^{23-15}\bigg):\bigg(7^{1+2+5}+5^{50-15}\bigg)=[/tex]
[tex]\bf \bigg(5^{35} +7^{8}\bigg):\bigg(7^{8}+5^{35}\bigg)=[/tex]
[tex]\bf \bigg(7^{8}+5^{35} \bigg):\bigg(7^{8}+5^{35}\bigg)=[/tex]
[tex]\red{\Large\boxed{\bf 1}}[/tex]
[tex]\it~~~[/tex]
[tex]\bf b)~~\Bigg[\bigg(2^{10} \bigg)^{8}+6^{5}\cdot3^{7}+2^{3^{2}}\Bigg]:\Bigg[\bigg(2^{5} \bigg)^{16}+6^{12}:2^{7}+2^{9}\Bigg]=[/tex]
[tex]\bf\bigg(2^{10\cdot8}+2^{5}\cdot3^{5}\cdot3^{7}+2^{9}\bigg):\bigg(2^{5\cdot 16}+2^{12}\cdot3^{12}:2^{7}+2^{9}\bigg)=[/tex]
[tex]\bf\bigg(2^{80}+2^{5}\cdot3^{5+7}+2^{9}\bigg):\bigg(2^{80}+2^{12-7}\cdot3^{12}+2^{9}\bigg)=[/tex]
[tex]\bf\bigg(2^{80}+2^{5}\cdot3^{12}+2^{9}\bigg):\bigg(2^{80}+2^{5}\cdot3^{12}+2^{9}\bigg)=[/tex]
[tex]\pink{\Large\boxed{\bf 1}}[/tex]
[tex]\it~~~[/tex]
[tex]\red{\Large \bf \star ~\underline{Formule~pentru~puteri}:}[/tex]
[tex]\Large \bf a^{0} = 1;[/tex]
[tex]\Large \bf (a^{n})^{m} = a^{n \cdot m};[/tex]
[tex]\Large \bf a^{n}\cdot a^{m} =a^{n+m};[/tex]
[tex]\Large \bf a^{n}: a^{m} =a^{n-m}[/tex]
[tex]\it~~[/tex]
P.S.: Dacă ești pe telefon te rog să glisezi spre stânga pentru a vedea întreaga rezolvare.
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