[tex]\it Fie\ x\ -\ m\breve asura\ unghiului \Rightarrow complementul\ lui\ x\ este\ \ 90^o-x \\ \\ 3(90^o-x)=x \Rightarrow 270^0-3x=x|_{+3x} \Rightarrow 270^o=4x|_{:2} \Rightarrow 2x=135^o \Rightarrow \\ \\ \Rightarrow 2x=134^o60'|_{:2} \Rightarrow x=67^o30'\\ \\ Complementul\ este:\\ \\ 90^o-67^o30'=89^o60'-67^o30'=22^o30'[/tex]
