rezolvati in Q ecuatia:
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[tex] \frac{3}{2}(x + \frac{1}{2} ) + \frac{1}{3} = \frac{5}{6} \\ \frac{3x}{2} + \frac{3}{4} + \frac{1}{3} = \frac{5}{6} \\ \frac{18x + 9 + 4}{12} = \frac{10}{12} \\ 18x + 13 = 10 \\ 18x = - 3 \\ x = - \frac{3}{18} = - \frac{1}{6} [/tex]