Răspuns: [tex]\mathrm{\boxed{a-b=3\cdot (5\sqrt{2}-4)}}[/tex]
Explicație pas cu pas:
[tex]\mathrm{a= \sqrt{15^{2} +15^{2}}=\sqrt{2\cdot15^{2}}\Rightarrow\boxed{a=15\cdot\sqrt{2}} }[/tex]
[tex]\mathrm{b= \sqrt{2^{4} \cdot3^{2}}=\sqrt{(2^{2})^{2} \cdot3^{2}}=\sqrt{(2^{2}\cdot3)^{2}}=2^{2}\cdot3\Rightarrow\boxed{b=12}}[/tex]
[tex]\mathrm{a-b=15 \sqrt{2}-12\Rightarrow\boxed{a-b=3\cdot (5\sqrt{2}-4)}}[/tex]
