Răspuns:
Explicație pas cu pas:
[tex]x = \sqrt{57} \\49 < 57 < 64\\\sqrt{49} <\sqrt{57} <\sqrt{64} \\7 < \sqrt{57} < 8\\8\geq x[/tex]
[tex]x= -\sqrt{\frac{36036}{12}} = -\sqrt{\frac{12*3003}{12}} = -\sqrt{3003}\\54^2 = 2916< 3003 < 3025 = 55^2\\\sqrt{54^2} <\sqrt{3003} <\sqrt{55^2} \\54 <\sqrt{3003} <55\\-54 > -\sqrt{3003} > -55\\-54 \geq x[/tex]
[tex]x=-\sqrt{789,1} \\28^2 = 784 < 789,1 < 841 = 29^2\\\sqrt{28^2} <\sqrt{789,1} <\sqrt{29^2} \\28 < \sqrt{789,1}< 29\\-28>-\sqrt{789,1}>-29 \\-28\geq x[/tex]
