.ALGEBRA CLASA A-VIIIA

[tex]\displaystyle{ -5 < \frac{3x+8}{2}< 4 }[/tex]
[tex]\displaystyle{ -10 < 3x + 8 < 4 }[/tex]
[tex]\displaystyle{ -18 < 3x < -4 }[/tex]
[tex]\displaystyle{ -6 < x < -\frac{4}{3} }[/tex]
x apartine intervalului deschis (-6, -4/3)
deci A = (-6, -4/3)
[tex]\displaystyle{ \frac{1}{6} < \frac{x}{4} + \frac{1}{3} < \frac{1}{2} }[/tex]
[tex]\displaystyle{ 2 < 3x + 4 < 6 }[/tex]
[tex]\displaystyle{ -2 < 3x < 2 }[/tex]
[tex]\displaystyle{ -\frac{2}{3} < x < \frac{2}{3} }[/tex]
B = (-2/3, 2/3)