Răspuns:
b)
[tex]=\sqrt{4*6} (\frac{7\sqrt{3} -5\sqrt{2} }{\sqrt{6}} )-3\sqrt{6}(\frac{6\sqrt{3} -5\sqrt{2} }{\sqrt{6}} )-\sqrt{25*2} =[/tex]
[tex]=2\sqrt{6}*\frac{7\sqrt{3} -5\sqrt{2} }{\sqrt{6}} -3\sqrt{6}*\frac{6\sqrt{3} -5\sqrt{2} }{\sqrt{6}} -5\sqrt{2}=[/tex]
[tex]=2(7\sqrt{3} -5\sqrt{2} ) -3(6\sqrt{3} -5\sqrt{2} }) -5\sqrt{2}=[/tex]
[tex]=14\sqrt{3} -10\sqrt{2} -18\sqrt{3} +15\sqrt{2} } -5\sqrt{2}=[/tex]
[tex]=-4\sqrt{3}[/tex]
d)
[tex]=\sqrt{35} *\frac{8\sqrt{7}-4\sqrt{5} }{\sqrt{35} }- \sqrt{4*35} *\frac{6\sqrt{7}-9\sqrt{5} }{\sqrt{35} } +\sqrt{4*49*5} =[/tex]
[tex]=8\sqrt{7}-4\sqrt{5} - 2*(6\sqrt{7}-9\sqrt{5} ) +14\sqrt{5} =[/tex]
[tex]=8\sqrt{7}-4\sqrt{5} - 12\sqrt{7}+18\sqrt{5} +14\sqrt{5} =[/tex]
[tex]=28\sqrt{5}-4\sqrt{7}[/tex]
Explicație pas cu pas:
