Răspuns:
Explicație pas cu pas:
log₂3 = a
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log₂96 = log₂(3·2⁵) = log₂3 + log₂2⁵ = a + 5·log₂2 = a+5
log₂(16/27) = log₂(2⁴·3⁻³) = log₂2⁴+log₂3⁻³ = 4 - 3a
log₆12 = log₂12/log₂6 = log₂(3·4) / log₂(3·2) =
= (log₂3 + log₂4)/(log₂3 + log₂2) = (a+2)/(a+1)
log₃54 = log₂54/lo₂3 = log₂(3³·2) / log₂3 =
= (log₂3³+log₂2) / log₂3 = (3a+1)/a
log₂₍₃8/9 = log₂ (8/9) / log₂ (2/3) =
= log₂ (2³/3²) / log₂ (2/3) =
= (3log₂2 - 2log₂3) / (log₂2 - log₂3)
= (3-2a) / (1-a) = (2a-3)/(a-1)
