Răspuns:
[tex]\frac{(2^8^0+9*18^5+2^3^2}{25^1^6+32*3^1^2+29}[/tex]
Explicație pas cu pas:
[(2¹⁰)⁸+6⁵×3⁷+2³²]:[25¹⁶+6¹²:2⁷+29]=
=(2⁸⁰+3²×18⁵+2³²):(25¹⁶+[tex]\frac{6^1^2}{2^7}[/tex]+29)
=2⁸⁰+9×18⁵+2³²):(25¹⁶+[tex]\frac{3^1^2*2^1^2}{2^7}[/tex]+29)
=(2⁸⁰+9×18⁵+2³²):(25¹⁶+3¹²×2⁵+29)
=(2⁸⁰+9×18⁵+2³²):(25¹⁶+3¹²×32+29)
=(2⁸⁰+9×18⁵+2³²):(25¹⁶+32×3¹²+29)
=[tex]\frac{(2^8^0+9*18^5+2^3^2}{25^1^6+32*3^1^2+29}[/tex]