Răspuns:
1.
[tex]36 = {2}^{2} \times {3}^{2} [/tex]
[tex]24 = {2}^{3} \times 3[/tex]
[tex]60 = {2}^{2} \times 3 \times 5[/tex]
[tex](36.24.60) = {2}^{2} \times 3 = 12[/tex]
[tex] {3}^{36} = ( {3}^{3} )^{12} = {27}^{12} [/tex]
[tex] {5}^{24} = ( {5}^{2} )^{24} = {25}^{24} [/tex]
[tex] {2}^{60} = ( {2}^{5} )^{12} = {32}^{12} [/tex]
[tex] {2}^{60} > {3}^{36} > {5}^{24} [/tex]
2.
[tex] {3}^{2x + 1} + {3}^{2x + 2} + {3}^{2x + 4} = {3}^{2x + 1} (1 + 3 + {3}^{3} ) = {3}^{2x + 1} \times 31[/tex]
[tex] {3}^{2x + 1} \times 31 = 1080[/tex]
Ceva nu e bine în redactarea exercițiului...
