Răspuns:
[tex]g)(a + 2)(x + 2) + 3a(x + 2) = (x + 2)(a + 2 + 3a) = (x + 2)(4a + 2) \\ h)(x + 2)(x - 3) + (x + 2)(2x + 1) = (x + 2)(x - 3 + 2x + 1) = (x + 2)(3x - 2) \\ i)(x + 1)(5x + 6) - (5x - 7)(x + 1) = (x + 1)(5x + 6 - (5x - 7)) = (x + 1)(5x + 6 - 5x + 7) = (x + 1) \times 13 \\ j) {(2x - 3)}^{2} - 4(2x - 3) \\ (2x - 3)(2x - 3 - 4 \times 1) = (2x - 3)(2x - 3 - 4) = (2x - 3)(2x - 7)[/tex]