Răspuns:
[tex]mg = \sqrt{\sqrt6*(\sqrt{6}+\sqrt{2} ) } } \\mg =\sqrt{\sqrt{6}*\sqrt{6}+\sqrt{6}*\sqrt{2} }\\mg =\sqrt{6+\sqrt{12} } \\mg =\sqrt{6+2\sqrt{3} } \\[/tex]
[tex]mg =\sqrt{\sqrt{2}*(\sqrt{6}+\sqrt{2} }\\mg=\sqrt{\sqrt{2}*\sqrt{6}+\sqrt{2} *\sqrt{2} }\\mg =\sqrt{\sqrt{12}+2 }\\mg=\sqrt{2\sqrt{3} +2}[/tex]
[tex]\sqrt{6+2\sqrt{3} } >\sqrt{2+2\sqrt{3} } \\6+2\sqrt{3} >2+2\sqrt{3}[/tex]
Explicație pas cu pas:
